If a current of 9mA flows through a 250 ohm resistor, what is the voltage drop across the resistor?

If a current of 9mA flows through a 250 ohm resistor, what is the voltage drop across the resistor?

• A. 12.5 volts
• B. 22.5 volts
• C. 0.225 volts
• D. 2.25 volts

Answer: (D)

To determine the voltage drop across a resistor, Ohm's Law can be applied, which states that Voltage (V) is equal to the current (I) multiplied by the resistance (R). The formula can be expressed as: V = I × R In this case, the current is given as 9 mA (which is equivalent to 0.009 A), and the resistance is 250 ohms. By substituting the known values into the formula: V = 0.009 A × 250 ohms V = 2.25 volts This calculation shows that the voltage drop across the 250-ohm resistor with a current of 9 mA is indeed 2.25 volts. Understanding this application of Ohm's Law is crucial for working with electrical circuits, as it allows technicians to calculate voltage drops and ensure proper functioning of circuits and components.

To determine the voltage drop across a resistor, Ohm's Law can be applied, which states that Voltage (V) is equal to the current (I) multiplied by the resistance (R). The formula can be expressed as:

V = I × R

In this case, the current is given as 9 mA (which is equivalent to 0.009 A), and the resistance is 250 ohms.

By substituting the known values into the formula:

V = 0.009 A × 250 ohms

V = 2.25 volts

This calculation shows that the voltage drop across the 250-ohm resistor with a current of 9 mA is indeed 2.25 volts. Understanding this application of Ohm's Law is crucial for working with electrical circuits, as it allows technicians to calculate voltage drops and ensure proper functioning of circuits and components.